(D) The $pH$ is calculated using the formula: $pH = -\log [H^{+}]$.Given $[H^{+}] = 2 \times 10^{-9} \ M$.$pH = -\log (2 \times 10^{-9})$$pH = -(\log

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(D) The $pH$ is calculated using the formula: $pH = -\log [H^{+}]$.Given $[H^{+}] = 2 \times 10^{-9} \ M$.$pH = -\log (2 \times 10^{-9})$$pH = -(\log 2 + \log 10^{-9})$$pH = -(\log 2 - 9)$$pH = 9 - \log 2$Since $\log 2 \approx 0.301$,$pH = 9 - 0.301 = 8.699 \approx 8.7$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Water hydrolysis and pH scale

Medium

The hydrogen ion concentration of the oceans is about $2 \times 10^{-9} \ M.$ What is the $pH$?

A
$8.85$
B
$9.3$
C
$7.85$
D
$8.7$

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6-2.Equilibrium-II (Ionic Equilibrium)

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Water hydrolysis and pH scale

The $[H^{+}]$ in lemon juice is found to be $0.0063 \ M$. What is the $pH$ value of lemon juice? $(\log 6.3 = 0.7993)$

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At $298 \ K$,the $pH$ of a $NaCl$ solution is $7$. If the solution is heated to $320 \ K$,which of the following statements is correct?

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$A$ solution has $pH = 5$. If it is diluted $100$ times,what will be the nature of the resulting solution?

Easy

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The concentration of hydrogen ions in a given solution is $6 \times 10^{-4} \ M$. The $pH$ of the solution is:

Medium

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When pure water is taken in a container and it absorbs $CO_2$ from the atmosphere,what will be the $pH$?

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The hydrogen ion concentration of the oceans is about $2 \times 10^{-9} \ M.$ What is the $pH$?

Similar Questions

The $[H^{+}]$ in lemon juice is found to be $0.0063 \ M$. What is the $pH$ value of lemon juice? $(\log 6.3 = 0.7993)$

At $298 \ K$,the $pH$ of a $NaCl$ solution is $7$. If the solution is heated to $320 \ K$,which of the following statements is correct?

$A$ solution has $pH = 5$. If it is diluted $100$ times,what will be the nature of the resulting solution?

The concentration of hydrogen ions in a given solution is $6 \times 10^{-4} \ M$. The $pH$ of the solution is:

When pure water is taken in a container and it absorbs $CO_2$ from the atmosphere,what will be the $pH$?

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